Following quiz provides Multiple Choice Questions (MCQs) related to Volume Calculation. You will have to read all the given answers and click over the correct answer. If you are not sure about the answer then you can check the answer using Show Answer button. You can use Next Quiz button to check new set of questions in the quiz.
Q 1 - The length, expansiveness and tallness of a cuboid are in the proportion 6:5:4 and its entire surface region is 33300 cm2. Its volume is:
Let length = 6x cm, breadth = 5x cm and height = 4x cm
Whole surface area = 2(lb+ bh + lh)
=2 (6x*5x + 5x *4x + 6x *4x) cm2 = (148x2) cm2
∴148x2= 33300 ⇒x2 = 225 ⇒x = √225 = 15 cm
∴L= 90 cm , B= 75 cm and h= 60 cm
∴Volume = (L*b*h) = (90*75*60) =405000cm3
Q 2 - A rectangular tank is 225m by 162 m at the base. With what pace must water stream into it through an opening 60cm by 45 cm that the level may be brought 20cm up in 5 hours?
Volume of water flown in 5hrs.= (225*162*20/100)= 7290 m3
Let the speed of the water be x meter /hr.
Water flown in 5 hrs. =(x*60/100*45/100*5) m3= (27x/20) m3
∴ 27x/20= 7290 ⇒ (7290*20/27) m = 5400m /hr.
Q 3 - The measurements of a cuboid are a, b,c units, its volume is V cubic units and its entire surface zone is S sq. units. At that point, 1/V=?
Product of areas of 3 adjacent faces = (Lb*bh*Lh)
=(L2*b2*h2) = (L*b*h) 2= V2
Q 5 - The region of three contiguous appearances of a cuboid are in the proportion 2:3:4 and its volume is 9000 cm3. The littlest side has a length of:
Let the area of the three adjacent faces be 2x, 3x and 4x then,
Lb= 2x, bh= 3x and Lh= 4x
∴ (Lb*bh*Lh) = 24x3 ⇒ (Lbh) 2 =(9000) 2= 81000000
⇒x3= 81000000/24= 27000000/8 ⇒x = 300/2= 150
∴ Lb= 300, bh =450 and Lh= 600 and Lbh= 9000
∴ h = 9000/300= 30cm, L= 9000/450 = 20cm, b= 9000/600= 15cm
Smallest side = 15 cm
Q 6 - The volume of a cuboid is twice that of a solid shape. On the off chance that the measurement of the cuboid is (9cm *8 cm* 6cm), the aggregate surface region of the block is:
2*volume of cube= volume of cuboid= (9*8*6) cm3
Volume of cube = (1/2 *9*8*6) cm3= 216cm3
∴ a3= 216 = (6) 3 ⇒a =6 cm
Total surface area = 6a2 = (6*6*6) cm2= 216cm2
Q 7 - A rectangular box measure s inside 1.6 m long, 1m expansive and 60 cm profound. The no. of cubical obstructs each of edge 20 cm that can be pressed inside the crate, is:
Q 8 - If the tallness of a barrel is expanded by 15% and the span of the base is diminished by 10%, then by what percent will its bended surface region change?
Let the original radius =r and height = h
Then curved surface area = 2πrh
New height = 115% of h = (115/100*h) = 23h/20
New radius = 90% of r = (90/100*r) = 9r/10
New curved surface area = (2π*9r/10*23h/20) = 207πrh/100
Increase = (207πrh/100-2 πrh) = 7 πrh/100
Increase %= (7 πrh/100*1/2 πrh*100) %= 3.5%
Q 9 - The bended surface zone of a round column is 528m2 and its volume is 2772 m3. The tallness of the column is:
