Following quiz provides Multiple Choice Questions (MCQs) related to Trains. You will have to read all the given answers and click over the correct answer. If you are not sure about the answer then you can check the answer using Show Answer button. You can use Next Quiz button to check new set of questions in the quiz.
Q 1 - The speed of a train 150 m long is 50 kmph. How much time will it take to pass a platform 600 m long ?
Speed =(50*5/18) m/sec. =125/9 m/sec Required time = (600+ 150)/ (125/9) sec.=(750*9/125)sec. =54 sec.
Q 2 - A train 100 m long crosses a bridge of length 100 m in 6 sec. The train will cross another bridge of length 200 m in:
Time taken to cover (100+100)m= 6 sec Speed of the train = 200/6 m/sec. Time taken to cover (100+200)m = (300*6/200) sec =9 sec.
Q 3 - Two trains are running in opposite side with speeds of 62 kmph and 40 kmph respectively. If the length of one train is 250m and they cross each other in 18 sec. , the length of the other train is
Let the length of the other train be x meters. Sum of their length = (250*x) m Relative speed = (62+40)kmph = 102kmph =(102*5/18) m/sec. = 85/3 m/sec. (250+x)/(85/3) =18 ⇒ 3(250+x) = (85*18) ⇒ 750+3x =1530 ⇒ 3x = 780 ⇒ x = 260 ∴ length of the other train = 260 m
Q 4 - A train 100 m in length passes a milestone in 10 sec. and another train of the same length is going in opposite direction in 8 sec. The speed of the second train is
Speed of the first train = (100/10)m/sec. = 10m/sec. Let the speed of the second train be x m/sec. 200/ (10+x) = 8 ⇒ 8(10+x) =200 ⇒ 8x = 120 ⇒ x =15 ∴ speed of the second train =15m/sec. = (15*18/5) =54km/hr
Q 5 - A train moving at the rate of 36 km per hour crosses a standing man in 10 sec. It will cross a platform 55m long, in
speed of the train = (36*5/18)m/sec. =10m/sec. Let the length of the second train be x meters. Then, x/10 =10 ⇒ x =100m Time taken by the train to cross the platform = (100+55)/10 sec.=31/2 sec.
Q 6 - A train is running at the rate of 40kmph. A man is going in the same direction parallel to the train at 25kmph . If the train crosses the man in 48 sec. , the length of the train is
relative speed = (40-25)kmph =15kmph =(15*5/18) m/sec. =25/6 m/sec. Length of the train = (25/6*48)m= 200 m.
Q 7 - A train X speeding with 120kmph cross another train Y, running in the same direction, in 2 min. If the length of the trains X and Y be 100 m and 200m respectively, What is the speed of train Y
let the speed of train y be x km/hr. Speed of x relative to y =(120-x) km/hr =[ (120-x)*5/18]m/sec. = (600-5x)/18 m/sec. 300/ (600-5x)/18 =120 ⇒120 (600-5x) =5400 ⇒ 600-5x =45 ⇒ 5x =555 ⇒ x =111 Speed of train y = 111km/hr