Answer - A
Explanation
Here a = 5, d = 8 - 5 = 3, n = 16
Using formula Tn = a + (n - 1)d
T16 = 5 + (16 - 1) x 3
= 50
Answer - C
Explanation
Here a = 4, d = 9 - 4 = 5
Using formula Tn = a + (n - 1)d
Tn = 4 + (n - 1) x 5 = 109 where 109 is the nth term.
=> 4 + 5n - 5 = 109
=> 5n = 109 + 1
=> n = 110 / 5
= 22
Answer - D
Explanation
Here a = 7, d = 13 - 7 = 6, Tn = 205
Using formula Tn = a + (n - 1)d
Tn = 7 + (n - 1) x 6 = 205 where 205 is the nth term.
=> 7 + 6n - 6 = 205
=> 6n = 205 - 1
=> n = 204 / 6
= 34
Q 4 - Which of the following is the first term of A.P. if 6th term is 12 and 8th term is 22?
A - -13
B - 13
C - 2
D - 1
Answer - A
Explanation
Using formula Tn = a + (n - 1)d
T6 = a + (6 - 1)d = 12 ...(i)
T8 = a + (8 - 1)d = 22 ...(ii)
Substract (i) from (ii)
=> 2d = 10
=> d = 5
Using (i)
a = 12 - 5d
= 12 - 25
= -13
Q 5 - Which of the following is the common difference of A.P. if 6th term is 12 and 8th term is 22?
A - 4
B - 5
C - 6
D - 7
Answer - B
Explanation
Using formula Tn = a + (n - 1)d
T6 = a + (6 - 1)d = 12 ...(i)
T8 = a + (8 - 1)d = 22 ...(ii)
Substract (i) from (ii)
=> 2d = 10
=> d = 5
Answer - C
Explanation
Using formula Tn = a + (n - 1)d
T6 = a + (6 - 1)d = 12 ...(i)
T8 = a + (8 - 1)d = 22 ...(ii)
Substract (i) from (ii)
=> 2d = 10
=> d = 5
Using (i)
a = 12 - 5d
= 12 - 25
= -13
∴ T16 = -13 + (16 - 1) x 5
= 75 - 13
= 62
Answer - D
Explanation
Here a = 5, d = 9 - 5 = 4, n = 17
Using formula Sn = (n/2)[2a + (n - 1)d]
S17 = (17/2)[2 x 5 + (17 - 1) x 4]
= (17/2)(10 + 64)
= 17 x 74 / 2
= 629
Answer - A
Explanation
Here a = 2, d = 5 - 2 = 3, Tn = 182
Using formula Tn = a + (n - 1)d
a + (n - 1)d = 182
=> 2 + (n - 1) x 3 = 182
=> 3n = 183
=> n = 61.
Using formula Sn = (n/2)[2a + (n - 1)d]
S61 = (61/2)[2 x 2 + (61 - 1) x 3]
= (61/2)(4 + 180)
= 61 x 184 / 2
= 5612
Answer - B
Explanation
Let've numbers are a - d, a and a + d
Then a - d + a + a + d = 15
=> 3a = 15
=> a = 5
Now (a - d)a(a + d) = 80
=> (5 - d) x 5 x (5 + d) = 80
=> 25 - d2 = 16
=> d2 = 9
=> d = +3 or -3
∴ numbers are either 2, 5, 8 or 8, 5, 2.
Answer - B
Explanation
Here a = 3, r = 6 / 3 = 2, T9 = ?
Using formula Tn = ar(n - 1)
T9 = 3 x 2(9 - 1)
=3 x 28
=3 x 256
=768
Q 11 - Which of the following is the first term of G.P. if 4th term is 54 and 9th term is 13122?
A - 2
B - 3
C - 4
D - 6
Answer - A
Explanation
Using formula Tn = ar(n - 1)
T4 = ar(4 - 1) = 54
=> ar3 = 54 ...(i)
T9 = ar(9 - 1) = 13122
=> ar8 = 13122 ...(ii)
Dividing (ii) by (i)
=> r5 = 13122 / 54 = 243 = (3)5
=> r = 3
Using (i)
a x 27 = 54
=> a = 2
Q 12 - Which of the following is the common ratio of G.P. if 4th term is 54 and 9th term is 13122?
A - 2
B - 3
C - 4
D - 6
Answer - B
Explanation
Using formula Tn = ar(n - 1)
T4 = ar(4 - 1) = 54
=> ar3 = 54 ...(i)
T9 = ar(9 - 1) = 13122
=> ar8 = 13122 ...(ii)
Dividing (ii) by (i)
=> r5 = 13122 / 54 = 243 = (3)5
=> r = 3
Answer - C
Explanation
Using formula Tn = ar(n - 1)
T4 = ar(4 - 1) = 54
=> ar3 = 54 ...(i)
T9 = ar(9 - 1) = 13122
=> ar8 = 13122 ...(ii)
Dividing (ii) by (i)
=> r5 = 13122 / 54 = 243 = (3)5
=> r = 3
Using (i)
a x 27 = 54
=> a = 2
∴ T6 = ar(6 - 1) = 2 x (3)5
= 2 x 243
= 486
Answer - A
Explanation
Let the numbers are y and 80 - y.
Then 3y = 5(80-y)
=> 8y = 400
∴ y = 50
and second number = 80 - 50 = 30.
Answer - B
Explanation
Let the number be y.
Then (y / 3) - (y / 5) = 16
=> 5y - 3y = 16 x 15 = 240
=> 2y = 240
∴ y = 120
Q 16 - What is the largest number among the three consecutive multiples of 3 if there sum is 90?
A - 21
B - 30
C - 33
D - 36
Answer - C
Explanation
Let the numbers be 3y , 3y + 3, 3y + 6
Now 3y + 3y + 3 + 3y + 6 = 90
=> 9y = 81
=> y = 9
=> largest number = 3y + 6 = 3 x 9 + 6
= 33
Answer - D
Explanation
Let the positive integer by y.
Then y2 - 15y = 16
=> y2 - 15y - 16 = 0
=> y2 - 16y + y - 16 = 0
=> y(y-16) + (y-16) = 0
=> (y+1)(y-16)= 0
∴ y = 16. as -1 is not a positive integer.
Q 18 - Find is the positive integer if twenty-three times of it is more than its square by 63.
A - 7
B - 8
C - 9
D - 10
Answer - A
Explanation
Let the positive integer by y.
Then 23y - 2y2 = 63
=> 23y - 2y2 - 63 = 0
=> 2y2 - 23y + 63 = 0
=> 2y2 - 14y - 9y + 63 = 0
=> 2y(y-7) - 9(y-7)= 0
=> (2y-9)(y-7)= 0
∴ y = 7. as 9/2 is not an integer.
Q 19 - Find the smallest of three numbers if numbers are in ratio of 3:2:5 and sum of their squares is 1862.
A - 13
B - 14
C - 12
D - 11
Answer - B
Explanation
Let've number as 3y, 2y and 5y.
Then 9y2 + 4y2 + 25y2 = 1862.
=> 38y2 = 1862
=> y2 = 1862 / 38 = 49
=> y = 7
∴ smallest number = 2y = 2 x 7 = 14.
Q 20 - Sum of digits of a two digit number is 10. If digits are interchanged, obtained number is 54 less than original number. What is the number?
A - 46
B - 64
C - 82
D - 28
Answer - C
Explanation
Let the ten's digit is x and unit digit of number is y.
Then x + y = 10 ...(i)
(10x + y) - (10y - x) = 54
=> 9x - 9y = 54
=> x - y = 6 ...(ii)
Adding (i) and (ii)
2x = 16
=> x = 8
Using (i)
y = 10 - x = 2
∴ number is 82.
