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Unit digit in 735 = (74)8 x 73
= 1 x 3 = 3
Unit digit in 348 = (34)12
= 1
Therefore, unit digit in 735 - 348 = 3 - 1 = 2
Q 2 - Which of the following numbers is completely divisible by 45?
45 = 5 x 9
So, co-primes are 5 and 9
For divisibility, the unit digits must be 0 or 5 and sum of digits must be divisible by 9.
The unit digit of 2025 is 5 and sum of digits is divisible by 9
Therefore, 2025 is completely divisible by 45.
7 as it has no positive divisors except 1.
Q 4 - It is being given that (232) + 1) is completely divisible by a whole number. Which of the following numbers is completely divisible by this number?
Let 232 = p
-> (232 + 1) = p + 1
Let (p + 1) be completely divisible by natural number Z. Then->
(296 + 1) = [(232)3 + 1]
As (p3 + 1) = (p + 1)(p2 - p + 1), which is completely divisible by Z, since (p + 1) is completely divisible by Z.
a = 6, d = 9, l = 123
Let number of terms be n
123 = a + (n - 1)d
123 = 6 + (n - 1)9
123 = 9n - 9
n = 14
Sn = n⁄2 (a + l)
= 14⁄2 (6 + 123)
= 7 x 129
= 903
795 = (74)23 x 73 So Unit digit in 795 = Unit digit in 1 x 343 = 3 358 = (34)14 x 32 So Unit digit in 358 = Unit digit in 1 x 9 = 9 So Unit digit in 795 - 358 = Unit digit in 13 - 9 = 4.
y =1024 x 976 = (1000 + 24) x (1000 - 24) Now using formula (a+b)(a-b)=a2-b2 y = (1000)2 - (24)2 = 1000000 - 576 = 999424
y = 106 x 106 - 94 x 94 = (106)2 - (94)2 = (100 + 6)2 - (100 - 6)2 Using formulae (a+b)2 = a2 + b2 + 2ab and (a-b)2 = a2 + b2 - 2ab (a+b)2 - (a-b)2 = 4ab ∴ y = 4 x 100 x 6 = 2400
Q 9 - Which of the following will always divide difference between squares of two consecutive even numbers completely?
let a = 2n , b = 2n + 2 => (b)2 - (a)2 = (2n + 2))2 - (2n)2 = 4[(n + 1)2 - (n)2] = 4(2n + 1) Which is always divisible by 4.
Q 10 - How many numbers are divisible by all 4,5 and 6 lying between 200 and 600.
Each number should be divisible by L.C.M. of 4, 5 and 6 i.e. 60. So numbers are 240, 300, 360, 420, 480, 540. Count: 6