Geometry - Online Quiz

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Following quiz provides Multiple Choice Questions (MCQs) related to Geometry. You will have to read all the given answers and click over the correct answer. If you are not sure about the answer then you can check the answer using Show Answer button. You can use Next Quiz button to check new set of questions in the quiz.

Questions and Answers

Q 1 - The sum of all angles around a point is

A - 0⁰

B - 90⁰

C - 180⁰

D - 360⁰

Answer : D

Explanation

The sum of all angle around a point is 360⁰ .

Q 2 - Two angles are complementary, if the sum of their measures is

A - 90⁰

B - 100⁰

C - 180⁰

D - 360⁰

Answer : A

Explanation

Two angle are complementary, if the sum of their measures is 90⁰.

Q 3 - In the given figure , AB || CD, ∠ABE =35⁰, ∠CDE = 65⁰ and ∠BED =x⁰. Then, x= ?

q 27

A - 30⁰

B - 100⁰

C - 125⁰

D - 145⁰

Answer : B

Explanation

Draw GEH ||AB||CD.
∠ BHE =∠ ABE = 35⁰ (alt .∠s)
∠ DEH =∠ CDE = 65⁰ (alt .∠s)
∴∠x=∠ BEH + ∠DEH = (35⁰ +65⁰)=100⁰.

a 27

Q 4 - In A ∆ABC ,∠A+∠B=65⁰ and∠B +∠C = 140⁰ . Then ∠B =?

A - 25⁰

B - 35⁰

C - 40⁰

D - 45⁰

Answer : A

Explanation

(∠A+∠B) +(∠B+∠C) =(65⁰+140⁰)= 205⁰
⇒ (∠A+∠B+∠C) +∠B =205⁰ ⇒ 180⁰ +∠B=205⁰
⇒ ∠B =(205-180)⁰ =25⁰

Q 5 - In A ∆ABC ,∠A-∠B=33⁰ and∠ B -∠C = 18⁰ . Then∠ B =?

A - 35⁰

B - 55⁰

C - 45⁰

D - 57 ⁰

Answer : B

Explanation

∠ A- ∠B = 33⁰ and ∠B -∠C =18⁰
⇒ A= 33+ B and C=B -18
= (33+B) + B + (B-18) =180
⇒ 3B =165 ⇒ B 55.
 ∴  ∠B =55⁰.

Q 6 - The perimeters of two similar triangles ∆ ABC and∆ PQR are 36cm and 24 cm . If PQ= 10cm, Then AB=?

A - 20/3 cm

B - 10 √6/3 cm

C - 15cm

D - 200/3 cm

Answer : C

Explanation

we have  AB/PQ = 36/24 ⇒ AB / 10 = 3/2 ⇒ AB = (3/2 * 10) = 15 cm.

Answer : C

Explanation

The angle in a semi-circle is a right angle.

Q 8 - In a cyclic quad. ABCD, ∠A=80⁰. Then ∠c =?

q 45

A - 80⁰

B - 160⁰

C - 100⁰

D - 120⁰

Answer : C

Explanation

Opposite angles of a cyclic quadrilateral are supplementary.
∴ ∠A + ∠C = 180 ⁰⇒ 80⁰ + C =180⁰ ⇒ C = 100⁰.

Q 9 - In the given fig. PAB is a secant and PT is a tangent to the circle from P. If PT = 4cm and AB = xcm , Then PB = ?

q 51

A - 2.5 cm

B - 2.6 cm

C - 2.25 cm

D - 2.75 cm

Answer : C

Explanation

PA *PB = PT2 ⇒ 4*(4+x)=25 ⇒ 4=x = 25/4 = 6.25 ⇒ x= 2.25 cm.

Q 10 - The lengths of the diagonals of a rhombus are 24cm and 18cm respectively. The length of each side of the rhombus is

A - 12 cm

B - 9 cm

C - 15 cm

D - 8 cm

Answer : C

Explanation

Let ABCD be a rhombus in which diagonal AC=24 cm and diagonal BD =18 cm . We know that the diagonal of a   rhombus bisect each other at right angle.
∴ OA = 1/2 AC =(1/2 *24 ) cm =12cm
OB = 1/2 BD = (1/2 *18 ) cm =9cm 
AB2 = OA2 + OB2 = (12) 2 +  92 = (144 +81) = 225 
⇒ AB = √225 = 15 cm.
∴ Each side of the rhombus is 15 cm.

a 55

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