Following quiz provides Multiple Choice Questions (MCQs) related to Basic Equations. You will have to read all the given answers and click over the correct answer. If you are not sure about the answer then you can check the answer using Show Answer button. You can use Next Quiz button to check new set of questions in the quiz.
The given equations are 2x+ y=8... (1) 4x-3y=-4 ...(2) On multiplying (1) by 3 and adding (2) to it, we get: 10x= 20 ⇒x= 2 Putting x= 2 in (1), we get: 4+ y = 8 ⇒y = 4 ∴ x= 2, y= 4
Putting y = x+3 in 2x+3y = 29, we get : 2x+3 (x+3) = 29 ⇒5x = 20 ⇒x= 4
Given 3x+7y = 75 ...(i) 5x-5 y= 25 ⇒x-y = 5...(ii) Multiplying (ii) by 7 and adding to (i), we get: 10 x = 110 ⇒x = 11 Putting x = 11 in (ii), we get: y=(11-5) = 6 ∴ x+y = (11+6) = 17
Q 4 - If x/4 + y/3= 5/12 and x/2+ y =1, then the estimation of (x+y) is:
Given equations are 3x+4y= 5 ...(i) and x+2y =2 ...(ii) On multiplying (ii) by 3 and subtracting (i) from it, we get 2y = 1 ⇒y = 1/2 Putting y = 1/2 in (ii), we get x+2*1/2 = 2 ⇒x+1= 2 ⇒x =1 ∴(x+y ) = (1+1/2 ) = 3/2
Q 5 - On the off chance that 2a+3 b= 17 and 2a+2-3b+1= 5 then:
Given equation are 2a +3b = 17 ...(i) 2a*22- 3b*3ⁱ= 5 ⇒4*2a- 3*3b= 5 ...(ii) Putting 2a = x and 3b= y, we get: x+y= 17 ...(iii) 4x-3y = 5...(iv) Multiplying (iii) by 3 and adding (iv) to it, we get: 7x= 56 ⇒x= 8 Putting x= 8 in (iii), we get: 8+ y = 17 ⇒y = 9 ∴ (2a= 8 = 23 ⇒a = 3) and (3b= 9= 32 ⇒b= 2) ∴ a= 3, b= 2
Q 6 - On the off chance that 4x+6y =32 and 4x-2y= 4, then 8y =?
4x+6y = 32...(i) 4x-2y = 4...(ii) On subtracting (ii) from (i), we get: 8 y= 28
Q 7 - The arrangement of 2x+3y=2 and 3x+2y =2 can be spoken to by a point in the direction plane in:
2x+3y = 2...(i) , 3x+2y= 2...(ii) Multiplying (i) by 2 and (ii) by 3 and subtracting, we get: -5x= -2 ⇒x= 2/5 Putting x= 2/5 in (i), we get 4/5+3y= 2 ⇒3y = (2-4/5) = 6/5 ⇒y = 6/5*1/3 =2/5 ∴ the solution can be represented by a point (2/5, 2/5) which lies in 1st quadrant.
Q 8 - The arrangement of mathematical statements 2x+ℏy= 11 and 5x-7y = 5 have no arrangement when:
For no solution , we have a₁/a₂ = b₁/b₂ ≠c₁/c₂ i.e. 2/5 = ℏ/-7 ≠11/5 ⇒ℏ= -14/5
Q 9 - The arrangement of comparisons x+2y = 3 and 2x+ 4y = 3 have:
Here a₁/a₂= 1/2, b₁/b₂=2/4=1/2 and c₁/c₂=3/3=1. ∴ a₁/a₂=b₁/b₂≠c₁/c₂. ∴Give system has no solution.
3x -5y=5 ...(i), 7x=5x+5y⇒2x-5y=0 ...(ii) On subtracting (ii) from (i), we get=5. 3*5-5y=5⇒5y=10⇒y=2. ∴(x-y) = (5-2) =3.