Answer - D
Explanation
Suppose, number of oranges bought = LCM of 6 and 4 = 12
∴CP = Re (10/6 * 12) = Re 20 and SP = Re (6/4 * 12) = Re 18
∴Loss% = (2/20 * 100)% = 10%
Answer - A
Explanation
(SP of 33m) - (CP of 33m) = Gain = SP of 11m
∴ SP of 22m = CP of 33m
Let CP of each meter be Re 1. Then, CP of 22m = Re 22.
Hence SP of 22m = Re 33.
∴ %Gain = 11/22 * 100
= 50%
Q 3 - Pure ghee costs Re 100 per kg. A shopkeeper mixes vegetable oil costing Re 50 per kg and sells the mixture at Re 96 per kg, making a profit of 20%. In what ratio does he mix the pure ghee with the vegetable oil.
A - 3:2
B - 2:3
C - 4:3
D - 3:1
Answer - A
Explanation
Mean Cost price = Re (100/120)*96 = Re 80 per kg
Apply rule of allegation,
there4; Required ratio = 30:20 = 3:2
Answer - C
Explanation
Let the CP of each article = Re 1.
Then CP of 20 articles = Re 20.
SP of 20 articles = CP of 25 articles = Re 25.
∴ Gain% = (5/20)*100% = 25%
Answer - D
Explanation
CP of 200 kg of mixture = Re (80 * 13.50) + (120 * 16) = Re 3000
SP = 116% of Re 3000 = Re (116/100)*3000 = Re 3480
∴Rate of SP = Re 3480/200 = Re 17.40/kg
Answer - B
Explanation
CP of 3 cookies = Re 1
SP of 3 cookies = 150% of Re 1 = 3/2
For Re 3/2, the man sells 3 cookies.
Hence for Re 1, number of cookies sold = 3*2/3 = 2
Q 7 - Anil buys a calculator for Re 600 and sells it to Vikash at 10% profit. Vikash sells it to Chandan for 5 % profit. Chandan after using it for certain time, sells it to Dinesh at a loss of 20%. For how much Chandan sell the calculator to Dinesh.
A - Re 550.50
B - Re 564.40
C - Re 554.40
D - None of these
Answer - C
Explanation
SP for Chandan = 600 * (110/100) * (105/100) * (80/100)
= 600 * 924/1000
= Re 554.40
Answer - A
Explanation
CP for X = 500 * (100/80) * (100/115) * (100/95) * (100/110)
= 500 * 10000/9614
= Re 520.07
Q 9 - A vendor when could not find buyers for his vegetable at Re 10/kg, reduced the rate to Re 8.10 per kg but uses a faulty weight of 900 gm in place of 1 kg weight. Find the percent change in the actual price or loss.
A - 8%
B - 8.10%
C - 9%
D - 10%
Answer - D
Explanation
After the price was reduced, 900 gm now costs Re 8.10.
Hence 1000gm will cost (1000/900)*8.10 = Re 9
% change in actual price or loss = [(10 - 9)/10]*100%
= 10%
Q 10 - A trader marks the SP of an object at a profit of 20%. Considering the demand o the object, he further increases the price by 10%. Find the final profit %.
A - 35%
B - 31%
C - 32%
D - 25%
Answer - C
Explanation
Let the CP = Re 100
∴ SP = 100 * (120/100) * (110/100)
= Re 132
Final profit = (132 - 100)*100%
= 32%
Answer - C
Explanation
CP = 4600 * (100/115)
=Re 4000
Loss% = [(4000-3600)/4000]*100%
= 10%
Q 12 - A seller sells a watch at 5% loss. If he had bought it at 20% more and sold it for Re 115 less, he would have incurred a loss of 40%. Find the cost price of the watch.
A - Re 500
B - Re 5000
C - Re 550
D - Re 450
Answer - A
Explanation
Assume CP = x
Selling price at the first case = (95/100)x
Selling price at the second case = (60/100)*(120/100)x
= (7200/10000)x
As per question,
(95/100)x - (7200/10000)x = 150
Or, x = Re 500
Answer - D
Explanation
CP = 540*(100/90)
= Re 600
New SP = 600*(95/100)
= Re 570
Q 14 - Ram sells chocolates at a profit of 20% for Re 60. What will be the percentage loss or gain if he reduces the price to Re 55 due to less demand.
A - 11%
B - -11%
C - 10%
D - -10%
Answer - C
Explanation
CP = 60*(100/120)
= Re 50
New SP = Re 55
Gain% = (5/50)*100
=10%
Q 15 - A shopkeeper buys rice for Re 1600. He had to sell 1/4th at a loss of 20%. If he is to make an overall gain of 10%, what percentage of profit he needs to make out of the remaining stock of rice?
A - 20%
B - 25%
C - 15%
D - 18%
Answer - A
Explanation
CP of 1/4th of the stock = 1600/4 = Re 400
SP of 1/4th of the stock = 400*(80/100)
=Re 320
In order to make a profit of 10% on total CP, the SP should be:
SP = 1600*(110/100)
= Re 1760
∴The SP for the remaining 3/4th of the stock
should be Re 1760 - Re 320 = Re 1440.
Cost Price of the 3/4th of stock
= Re 1600 - Re 400 = Re 1200.
∴%Gain = [(1440-1200)/1200*100}]
= (240/1200)*100
= 20%
Answer - B
Explanation
10% of Re 110 = Re 11
Cost of 2 kg of wheat at new price = Re 11
So, cost of 1 kg of wheat at new price = Re 5.50 = Re 11/2
Original Price = (11/2)*(100/110)
= Re 5 per kg
Q 17 - 10 kg of rice costs as much as 20 kg of wheat, 25 kg of wheat costs as much as 2kg of tea, 5 kg of tea costs as much as 25kg of sugar. Find the cost of 6 kg of sugar if 14 kg of rice costs Re 32.
A - Re 50
B - Re 55
C - Re 60
D - Re 65
Answer - C
Explanation
4 kg of rice costs Re 32
∴10kg of rice will cost = (32/4)*10 = Re 80
20 kg of wheat costs Re 80.
∴25kg of wheat costs = (80/20)*25 = Re 100
2kg of tea costs Re 100
∴5 kg of tea costs = (100/2)*5 = Re 250
25kg of sugar costs Re 250.
∴6 kg of sugar costs = (250/25)*6 = Re 60
Answer - A
Explanation
Let CP = x paisa.
Initial SP = x*(120/100) paisa
As per question,
120x/100 + 25 = (145/100)x
or, 145x/100 - 120x/100 = 25
or, 25x/100 = 25
or, x = 100 paisa
CP = 100 paisa or Re 1.
Initial SP = 120 paisa or Re 1.20.
Answer - C
Explanation
Applying direct formula, %loss = (16/10)2%
= 64/25%
= 2.56%
Q 20 - An uneducated retailer marks all his goods at 50% above the cost price and thinking that he will still make 25% profit, offers a discount of 25% on the marked price. What is his actual profit on the sales?
A - 10%
B - 12.50%
C - 11.50%
D - 12%
Answer - B
Explanation
Let CP = Re 100.
The, marked price, MP = Re 150
SP = 75% of Re 150 = Re 112.50
∴ Gain% = 12.50%
