Q 1 − A train can cover a distance of 180 km in 5 hours. What is the speed of the train? Mention it in m/s.
Options :
Answer - C
Explanation
Speed of the train is 180/5 = 36 kmph. 36 × 5/18 = 10 m/s.
Q 2 − P and Q can finish a work in 15 & 10 days. Q starts the work and leaves it after 5 days .The number of days in which P can complete the work is
Options :
Answer - C
Explanation
Q ‘s 1 day work = 1/10
Q worked for 5 days
Q 5 day work = 5/10 = 1/2
Remaining work = 1 - 1/2 = 1/2
Let P complete the remaining work in x days,
x/15 = 1/2
x = 7 1/2
Q 3 − P is thrice as good workman as Q and is therefore able to finish the work in 60 days less than Q. Q can finish the work in
Options :
Answer - C
Explanation
Let Q takes = x days
P takes = (x-60) days
Q 5 day work = 5/10 = 1/2
Work done by P in 1 day = work done by Q in 1 day
1/x-60 = 3/x, solving it
x = 90
Q 4 − Average of 5 terms is 10. Average of first two terms is 7, and last two terms is 13? What is the value of third term?
Options :
Answer - C
Explanation
Total of 5 terms = 10 × 5 = 50
Total of first two terms = 2 × 7 = 14
Total of last two terms = 13 × 2 = 26
Third term = 50 - (14 + 26) = 10
Q 5 − A bag contain Rs 150 paisa and 25 paisa coins in the ratio 8:9:11. If the total money in the bag is Rs. 366. Find the number of Rs 25 paisa coins?
Options :
Answer - C
Explanation
Let number of coins of each denomination be x.
Then 1 × 8x + ½ × 9x + 1/4 × 11x = 366 61 x/4 = 366 = x = 24.
Hence, 25 paisa coins = 11x = 11 x 24 = 264.
Q 6 − Total weight of A & B is 120 kg. If A weights 30 kg more than B? What is ratio of B: A?
Options :
Answer - B
Explanation
Let B weight = x then
A weight = x + 30, then
Total weight = x + x + 30 = 2x + 30 = 120kg x = 45. Hence, B weight = 45, A = 75
So ratio = 3:5 = 0.6
Q 7 − The average age 6 students is 17.5 years. When one student left the class, average age becomes 16 years. What is age of the student who left?
Options :
Answer - B
Explanation
Total age of 6 students = 17.5 × 6 = 105
After one left. Total age of 5 students = 5 × 16 = 80
Left student age = 105 - 80 = 25 years
Q 8 − Rs. 41517 is distributed among A,B, and C in the ratio of 3:7:11? What is B’s share?
Options :
Answer - C
Explanation
B share = 41517 × 7/21 = 1508
Q 9 − 12 year old A is three times as old as his brother B. What should be A’s age to be twice as that of B?
Options :
Answer - A
Explanation
A's present age = 12 years, B's present age = 4 years. Let A be twice as old as B after x years from now. Then, 12 = 2 (4 + x) 12 + x = 8 + 2x x = 4.
Hence, A's required age = 12 + x = 16 years
Q 10 − The addition of ages of Ramesh and Bighnesh is 45 years 4 years ago. What will be the summation of their ages 6 years hence?
Options :
Answer - C
Explanation
The summation of ages will be 45 + 10 + 10 = 65. Hence, option C.