Finding the LCD of Two Fractions Online Quiz
Following quiz provides Multiple Choice Questions (MCQs) related to Finding the LCD of Two Fractions . You will have to read all the given answers and click over the correct answer. If you are not sure about the answer then you can check the answer using Show Answer button. You can use Next Quiz button to check new set of questions in the quiz.
Answer : A
Explanation
Step 1:
LCD of $\frac{3}{4}$ , $\frac{7}{10}$ is LCM of 4 and 10
Step 2:
Prime factorization of 4 and 10 is
4 = 2 × 2; 10 = 2 × 5
Step 3:
LCD is the product of most occurrence of the prime factors
LCD = 2 × 2 × 5 = 20
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Answer : D
Explanation
Step 1:
LCD of $\frac{5}{9}$ , $\frac{8}{15}$ is LCM of 9 and 15
Step 2:
Prime factorization of 9 and 15 is
9 = 3 × 3; 15 = 3 × 5
Step 3:
LCD is the product of most occurrence of the prime factors
LCD = 3 × 3 × 5 = 45
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Answer : C
Explanation
Step 1:
LCD of $\frac{3}{7}$ , $\frac{4}{8}$ is LCM of 7 and 8
Step 2:
Prime factorization of 7 and 8 is
7 is prime; 8 = 2 × 2 × 2
Step 3:
LCD is the product of most occurrence of the prime factors
LCD = 2 × 2 × 2 × 7 = 56
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Answer : B
Explanation
Step 1:
LCD of $\frac{3}{8}$ , $\frac{5}{12}$ is LCM of 8 and 12
Step 2:
Prime factorization of 8 and 12 is
8 = 2 × 2 × 2; 12 = 2 × 2 × 3
Step 3:
LCD is the product of most occurrence of the prime factors
LCD = 2 × 2 × 2 × 3 = 24
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Answer : B
Explanation
Step 1:
LCD of $\frac{7}{5}$ , $\frac{5}{4}$ is LCM of 5 and 4
Step 2:
Prime factorization of 5 and 4 is
5 is prime; 4 = 2 × 2
Step 3:
LCD is the product of most occurrence of the prime factors
LCD = 2 × 2 × 5 = 20
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Answer : C
Explanation
Step 1:
LCD of $\frac{4}{5}$ , $\frac{7}{15}$ is LCM of 5 and 15
Step 2:
Prime factorization of 5 and 15 is
5 is prime; 15 = 3 × 5
Step 3:
LCD is the product of most occurrence of the prime factors
LCD = 3 × 5 = 15
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Answer : A
Explanation
Step 1:
LCD of $\frac{1}{8}$ , $\frac{5}{6}$ is LCM of 8 and 6
Step 2:
Prime factorization of 8 and 6 is
8 = 2 × 2 × 2; 15 = 2 × 3
Step 3:
LCD is the product of most occurrence of the prime factors
LCD = 2 × 2 × 2 × 3 = 24
Show Answer
Answer : D
Explanation
Step 1:
LCD of $\frac{3}{4}$ , $\frac{2}{9}$ is LCM of 4 and 9
Step 2:
Prime factorization of 4 and 9 is
4 = 2 × 2; 9 = 3 × 3
Step 3:
LCD is the product of most occurrence of the prime factors
LCD = 2 × 2 × 3 × 3 = 36
Show Answer
Answer : D
Explanation
Step 1:
LCD of $\frac{3}{8}$ , $\frac{7}{10}$ is LCM of 8 and 10
Step 2:
Prime factorization of 8 and 10 is
8 = 2 × 2 × 2; 10 = 2 × 5
Step 3:
LCD is the product of most occurrence of the prime factors
LCD = 2 × 2 × 2 × 5 = 40
Show Answer
Answer : A
Explanation
Step 1:
LCD of $\frac{5}{6}$ , $\frac{8}{15}$ is LCM of 6 and 15
Step 2:
Prime factorization of 6 and 15 is
6 = 2 × 3; 15 = 3 × 5
Step 3:
LCD is the product of most occurrence of the prime factors
LCD = 2 × 3 × 5 = 30
Show Answer
finding_lcd_of_two_fractions.htm
