Following quiz provides Multiple Choice Questions (MCQs) related to Areas of rectangles with the same perimeter. You will have to read all the given answers and click over the correct answer. If you are not sure about the answer then you can check the answer using Show Answer button. You can use Next Quiz button to check new set of questions in the quiz.
Step 1:
Perimeter of given rectangle = 2(l + w) = 2(8 + 2)= 20; Area = l × w = 8 × 2 = 16 square units
Step 2:
One possible rectangle with same perimeter has dimensions 7×3: Its perimeter = 2(7 + 3) = 20
Its area that is different = 7×3 = 21 square units
Step 1:
Perimeter of given rectangle = 2(l + w) = 2(4 + 5) = 18; Area = l × w = 4 × 5 = 20 square units
Step 2:
One possible rectangle with same perimeter has dimensions 6×3. Its perimeter = 2(6 + 3) = 18
Its area that is different = 6×3 = 18 square units
Step 1:
Perimeter of given rectangle = 2(l + w) = 2(9 + 4) = 26; Area = l × w = 9 × 4 = 36 square units
Step 2:
One possible rectangle with same perimeter has dimensions 8×5; Its perimeter = 2(8 + 5) = 26
Its area that is different = 8×5 = 40 square units
Step 1:
Perimeter of given rectangle = 2(l + w) = 2(9 + 6) = 30; Area = l × w = 9 × 6 = 54 square units
Step 2:
One possible rectangle with same perimeter has dimensions 8×7; Its perimeter = 2(7 + 8) = 30
Its area that is different = 7×8 = 56 square units
Step 1:
Perimeter of given rectangle = 2(l + w) = 2(7 + 2) = 18; Area = l × w = 7 × 2 = 14 square units
Step 2:
One possible rectangle with same perimeter has dimensions 6×3; Its perimeter = 2(6 + 3) = 18
Its area that is different = 6×3 = 18 square units
Step 1:
Perimeter of given rectangle = 2(l + w) = 2(8 + 5) = 26; Area = l × w = 8 × 5 = 40 square units
Step 2:
One possible rectangle with same perimeter has dimensions 7×6; Its perimeter = 2(7 + 6) = 26
Its area that is different = 7×6 = 42 square units
Step 1:
Perimeter of given rectangle = 2(l + w) = 2(7 + 2) = 18; Area = l × w = 7 × 2 = 14 square units
Step 2:
One possible rectangle with same perimeter has dimensions 6×3; Its perimeter = 2(6 + 3) = 18
Its area that is different = 6×3 = 18 square units
Step 1:
Perimeter of given rectangle = 2(l + w) = 2(6 + 2) = 16; Area = l × w = 6 × 2 = 12 square units
Step 2:
One possible rectangle with same perimeter has dimensions 5×3; Its perimeter = 2(5 + 3) = 16
Its area that is different = 5×3 = 15 square units
Step 1:
Perimeter of given rectangle = 2(l + w) = 2(8 + 4) = 24; Area = l × w = 8 × 4 = 32 square units
Step 2:
One possible rectangle with same perimeter has dimensions 7×5; Its perimeter = 2(7 + 5) = 24
Its area that is different = 7×5 = 35 square units
Step 1:
Perimeter of given rectangle = 2(l + w) = 2(6 + 3) = 18; Area = l × w = 6 × 3 = 18 square units
Step 2:
One possible rectangle with same perimeter has dimensions 5×4; Its perimeter = 2(5 + 4) = 18
Its area that is different = 5×4 = 20 square units