Microwave Engineering - E-H Plane Tee

Characteristics of E-H Plane Tee

If a signal of equal phase and magnitude is sent to port 1 and port 2, then the output at port 4 is zero and the output at port 3 will be the additive of both the ports 1 and 2.
If a signal is sent to port 4, (E-arm) then the power is divided between port 1 and 2 equally but in opposite phase, while there would be no output at port 3. Hence, $S_{34}$ = 0.
If a signal is fed at port 3, then the power is divided between port 1 and 2 equally, while there would be no output at port 4. Hence, $S_{43}$ = 0.
If a signal is fed at one of the collinear ports, then there appears no output at the other collinear port, as the E-arm produces a phase delay and the H-arm produces a phase advance. So, $S_{12}$ = $S_{21}$ = 0.

Properties of E-H Plane Tee

The properties of E-H Plane Tee can be defined by its $\left [ S \right ]_{4\times 4}$ matrix.

It is a 4×4 matrix as there are 4 possible inputs and 4 possible outputs.

$[S] = \begin{bmatrix} S_{11}& S_{12}& S_{13}& S_{14}\\ S_{21}& S_{22}& S_{23}& S_{24}\\ S_{31}& S_{32}& S_{33}& S_{34}\\ S_{41}& S_{42}& S_{43}& S_{44} \end{bmatrix}$ ........ Equation 1

As it has H-Plane Tee section

$S_{23} = S_{13}$........ Equation 2

As it has E-Plane Tee section

$S_{24} = -S_{14}$........ Equation 3

The E-Arm port and H-Arm port are so isolated that the other won't deliver an output, if an input is applied at one of them. Hence, this can be noted as

$S_{34} = S_{43} = 0$........ Equation 4

From the symmetry property, we have

$S_{ij} = S_{ji}$

$S_{12} = S_{21}, S_{13} = S_{31}, S_{14} = S_{41}$

$S_{23} = S_{32}, S_{24} = S_{42}, S_{34} = S_{43}$........ Equation 5

If the ports 3 and 4 are perfectly matched to the junction, then

$S_{33} = S_{44} = 0$........ Equation 6

Substituting all the above equations in equation 1, to obtain the $[S]$ matrix,

$[S] = \begin{bmatrix} S_{11}& S_{12}& S_{13}& S_{14}\\ S_{12}& S_{22}& S_{13}& -S_{14}\\ S_{13}& S_{13}& 0& 0\\ S_{14}& -S_{14}& 0& 0 \end{bmatrix}$........ Equation 7

From Unitary property, $[S][S]^\ast = [I]$

$\begin{bmatrix} S_{11}& S_{12}& S_{13}& S_{14}\\ S_{12}& S_{22}& S_{13}& -S_{14}\\ S_{13}& S_{13}& 0& 0\\ S_{14}& -S_{14}& 0& 0 \end{bmatrix} \begin{bmatrix} S_{11}^{*}& S_{12}^{*}& S_{13}^{*}& S_{14}^{*}\\ S_{12}^{*}& S_{22}^{*}& S_{13}^{*}& -S_{14}^{*}\\ S_{13}& S_{13}& 0& 0\\ S_{14}& -S_{14}& 0& 0 \end{bmatrix}$

$ = \begin{bmatrix} 1& 0& 0& 0\\ 0& 1& 0& 0\\ 0& 0& 1& 0\\ 0& 0& 0& 1 \end{bmatrix}$

$R_1C_1 : \left | S_{11} \right |^2 + \left | S_{12} \right |^2 + \left | S_{13} \right |^2 = 1 + \left | S_{14} \right |^2 = 1$ ......... Equation 8

$R_2C_2 : \left | S_{12} \right |^2 + \left | S_{22} \right |^2 + \left | S_{13} \right |^2 = 1 + \left | S_{14} \right |^2 = 1$ ......... Equation 9

$R_3C_3 : \left | S_{13} \right |^2 + \left | S_{13} \right |^2 = 1$ ......... Equation 10

$R_4C_4 : \left | S_{14} \right |^2 + \left | S_{14} \right |^2 = 1$ ......... Equation 11

From the equations 10 and 11, we get

$S_{13} = \frac{1}{\sqrt{2}}$........ Equation 12

$S_{14} = \frac{1}{\sqrt{2}}$........ Equation 13

Comparing the equations 8 and 9, we have

$S_{11} = S_{22}$ ......... Equation 14

Using these values from the equations 12 and 13, we get

$\left | S_{11} \right |^2 + \left | S_{12} \right |^2 + \frac{1}{2} + \frac{1}{2} = 1$

$\left | S_{11} \right |^2 + \left | S_{12} \right |^2 = 0$

$S_{11} = S_{22} = 0$ ......... Equation 15

From equation 9, we get $S_{22} = 0$ ......... Equation 16

Now we understand that ports 1 and 2 are perfectly matched to the junction. As this is a 4 port junction, whenever two ports are perfectly matched, the other two ports are also perfectly matched to the junction.

The junction where all the four ports are perfectly matched is called as Magic Tee Junction.

By substituting the equations from 12 to 16, in the $[S]$ matrix of equation 7, we obtain the scattering matrix of Magic Tee as

$$[S] = \begin{bmatrix} 0& 0& \frac{1}{2}& \frac{1}{\sqrt{2}}\\ 0& 0& \frac{1}{2}& -\frac{1}{\sqrt{2}}\\ \frac{1}{\sqrt{2}}& \frac{1}{\sqrt{2}}& 0& 0\\ \frac{1}{\sqrt{2}}& -\frac{1}{\sqrt{2}}& 0& 0 \end{bmatrix}$$

We already know that, $[b]$ = $[S] [a]$

Rewriting the above, we get

$$\begin{vmatrix} b_1\\ b_2\\ b_3\\ b_4 \end{vmatrix} = \begin{bmatrix} 0& 0& \frac{1}{2}& \frac{1}{\sqrt{2}}\\ 0& 0& \frac{1}{2}& -\frac{1}{\sqrt{2}}\\ \frac{1}{\sqrt{2}}& \frac{1}{\sqrt{2}}& 0& 0\\ \frac{1}{\sqrt{2}}& -\frac{1}{\sqrt{2}}& 0& 0 \end{bmatrix} \begin{vmatrix} a_1\\ a_2\\ a_3\\ a_4 \end{vmatrix}$$

Applications of E-H Plane Tee

Some of the most common applications of E-H Plane Tee are as follows −

E-H Plane junction is used to measure the impedance − A null detector is connected to E-Arm port while the Microwave source is connected to H-Arm port. The collinear ports together with these ports make a bridge and the impedance measurement is done by balancing the bridge.
E-H Plane Tee is used as a duplexer − A duplexer is a circuit which works as both the transmitter and the receiver, using a single antenna for both purposes. Port 1 and 2 are used as receiver and transmitter where they are isolated and hence will not interfere. Antenna is connected to E-Arm port. A matched load is connected to H-Arm port, which provides no reflections. Now, there exists transmission or reception without any problem.
E-H Plane Tee is used as a mixer − E-Arm port is connected with antenna and the H-Arm port is connected with local oscillator. Port 2 has a matched load which has no reflections and port 1 has the mixer circuit, which gets half of the signal power and half of the oscillator power to produce IF frequency.

In addition to the above applications, an E-H Plane Tee junction is also used as Microwave bridge, Microwave discriminator, etc.

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